How do you solve #2x + 6\leq - 4#?
2 Answers
Sep 26, 2016
Explanation:
Subtract 6 from both sides of the inequation.
#2xcancel(+6)cancel(-6)<=-4-6#
#rArr2x<=-10# To solve for x, divide both sides by 2.
#(cancel(2) x)/cancel(2)<=(-10)/(2)#
#rArrx<=-5" is the solution"#
Sep 26, 2016
Solve for x by combining like terms
Explanation:
Subract 6 from both sides
Get x by itself, divide by 2