How do you solve #2x + 6\leq - 4#?

2 Answers
Sep 26, 2016

#x<=-5#

Explanation:

Subtract 6 from both sides of the inequation.

#2xcancel(+6)cancel(-6)<=-4-6#

#rArr2x<=-10#

To solve for x, divide both sides by 2.

#(cancel(2) x)/cancel(2)<=(-10)/(2)#

#rArrx<=-5" is the solution"#

Sep 26, 2016

Solve for x by combining like terms

Explanation:

#2x + 6\leq -4#

Subract 6 from both sides
#2x\leq -10#

Get x by itself, divide by 2
#x\leq -5#