Question #b6f66

Question

1277 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-27T10:29:57

#2/t#

#s^-1(t^-1)/s^-1+t^-1#

Let's simplify first and attend to the negative indices..

#cancel(s^-1)(t^-1)/cancel(s^-1)+t^-1#

=#t^-1 + t^-1#

=#1/t + 1/t#

As these are like terms they can be added to give #2/t#

HOwever, if we want factors, we can use #1/t) as the common factor:

#1/t + 1/t = 1/t(1+1)#

But this gives the same outcome..

#1/t (2) = 2/t#