How do you simplify #(-3x^2y^3)^4#?

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Answer 1 · 2016-09-27T10:38:10

#81x^8y^12#

Recall: two of the laws of indices:

#(x^p)^q = x^(pq)" "larr# (multiply the indices)

#(xy)^p = x^p y^p" "larr# (each factor is raised to the power)

Apply the laws to each factor separately

#(-3x^2y^3)^4 = (-3)^4 xx (x^(2))^4 xx y^3)^4#

=# +81 xx x^8 xx y^12#

=#81x^8y^12#