If 24 L24L of a gas at room temperature exerts a pressure of 8 kPa8kPa on its container, what pressure will the gas exert if the container's volume changes to 8 L8L?

1 Answer
Sep 28, 2016

24kPa24kPa

Explanation:

Let's identify the known and unknown variables:

color(violet)("Knowns:")Knowns:
- Initial Volume
- Final Volume
- Initial Pressure

color(orange)("Unknowns:")Unknowns:
- Final Pressure

We can obtain the answer using Boyle's Law thescienceclassroom.orgthescienceclassroom.org

The numbers 1 and 2 represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by V_2V2 in order to get P_2P2 by itself like this:
P_2=(P_1xxV_1)/V_2P2=P1×V1V2

Now all we do is plug in the values and we're done!

P_2= (8kPa xx 24cancel"L")/(8\cancel"L") = 24kPa