Question

Question #22044

Answer 1

In interval `0<=x<=2pi ; x=pi/4 and x=(7pi)/4`

Explanation:

`cos^2x=1/2 or cosx= 1/sqrt2`. We know `cos(pi/4)=1/sqrt2 and cos(2pi-pi/4)= cos((7pi)/4)=1/sqrt2 :. x=pi/4 and x=(7pi)/4` in interval `0<=x<=2pi`[Ans]