Question

How do you solve `3(cosx-1)=3-4cosx` in the interval `0<=x<=2pi`?

Answer 1

`x=+-0.541099526+2pin`

Explanation:

`3(cosx-1)=3-4cosx`

`3cosx-3=3-4cosx`

`3cosx+4cosx=3+3`

`7cosx = 6`

`cosx = 6/7`

`x=cos^-1 (6/7)`

`x=+-0.541099526+2pin`