How do you differentiate #y=(e^x(x^2-7))#?

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Answer 1 · 2016-10-05T15:11:39

#f'(x)=e^x(x^2+2x-7)#

You have to use the Product Rule

#f'(x)=uv'+u'v#

#u=e^x#
#u'=e^x#

#v=x^2-7#
#v'=2x#

#f'(x)=e^x2x+e^x(x^2-7)#

Factor out #e^x#

#f'(x)=e^x(x^2+2x-7)#