Question

Question #4099b

Answer 1

`132,000`

Explanation:

Let us assume that the population in 1999 is `x`

So `x + 8% "of " x =142,560`

`x+8/100x=142,560`

`108/100x=142,560`

`x=14,2560xx100/108`

`x=132,000`

Answer 2

`132,000` in 1999

Explanation:

This is an example of a reverse percentage where we know the value AFTER an increase has happened, but we do not know what the original amount was.

Do NOT be tempted to just find `8%` of the population in 2000 and subtract!

Here is a different approach from how Annie did it.

Percentages are always in direct proportion.
Let's compare what we know.

Let the population in 1999 be `x`
We can consider that as `100%`

In 2000, the population had increased by `8%`
The population of 142,560 represents `108%`

`x/100 = (142,560)/108`

`x = (142,560xx100)/108`

`x = 132,000`