Question

Question #17f7b

Answer 1

`-oo`

Explanation:

`lim_(x to 0^+) (sen x ln x )/x`

The limit of the products in the product of the limits
`= lim_(x to 0^+) (sen x )/x lim_(x to 0) ln x`

As we have

`= lim_(x to 0^+) (sen x )/x =1` which is one of the fundamental trig limits

And

`lim_(x to 0^+) ln x = =- oo`