How do you divide $| 40 | \div ∣ ∣ {(- 2)}^{3} ∣ ∣$ $|40| \div |( - 2)^{3} |$ ?

Question

How do you divide $| 40 | \div ∣ ∣ {(- 2)}^{3} ∣ ∣$ $|40| \div |( - 2)^{3} |$ ?

1 Answer

Impact of this question

1732 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-08T10:27:55

5

Explanation:

The $absolute value$ $color(blue)"absolute value"$ can be positive/negative.

That is |4|= 4 and |-4| = 4

Hence |40|=40 and $∣ ∣ {(- 2)}^{3} ∣ ∣ = | - 8 | = 8$ $|(-2)^3|=|-8|=8$

$\Rightarrow | 40 | \div ∣ ∣ {(- 2)}^{3} ∣ ∣ = 40 \div 8 = 5$ $rArr|40|÷|(-2)^3|=40÷8=5$

Science

Math

Humanities

... and beyond

How do you divide $| 40 | \div ∣ ∣ {(- 2)}^{3} ∣ ∣$ $|40| \div |( - 2)^{3} |$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide |40|÷∣∣(−2)3∣∣|40| \div |( - 2)^{3} |?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $| 40 | \div ∣ ∣ {(- 2)}^{3} ∣ ∣$ $|40| \div |( - 2)^{3} |$ ?