Question

Question #95ec3

Answer 1

K E of an object of mass m and velocity v is given by the formula

`E_k=1/2mv^2`

For first bullet `m=4.0 g=4xx10^-3kg and "velocity"= 100" m/s"`

Its KE `E_(k1)=1/2xx4xx10^-3xx100^2=20J=20xx10^7erg`

In Calorie KE `E_(k1)=20/4.2cal~~4.762cal`

For 2nd bullet `m=8.0 g=8xx10^-3kg and "velocity"= 100" m/s"`

Its KE `E_(k2)=1/2xx8xx10^-3xx100^2=40J=40xx10^7erg`

In Calorie KE `E_(k2)=40/4.2cal~~9.524cal`