Question #95ec3

1 Answer
Oct 9, 2016

K E of an object of mass m and velocity v is given by the formula

# E_k=1/2mv^2#

For first bullet #m=4.0 g=4xx10^-3kg and "velocity"= 100" m/s"#

Its KE #E_(k1)=1/2xx4xx10^-3xx100^2=20J=20xx10^7erg#

In Calorie KE #E_(k1)=20/4.2cal~~4.762cal#

For 2nd bullet #m=8.0 g=8xx10^-3kg and "velocity"= 100" m/s"#

Its KE #E_(k2)=1/2xx8xx10^-3xx100^2=40J=40xx10^7erg#

In Calorie KE #E_(k2)=40/4.2cal~~9.524cal#