How do you determine p(c) given $p (x) = x^{4} - 2 x^{2} + 4$ $p(x)=x^4-2x^2+4$ and c=3/2?

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How do you determine p(c) given $p (x) = x^{4} - 2 x^{2} + 4$ $p(x)=x^4-2x^2+4$ and c=3/2?

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Answer 1 · 2016-10-09T15:38:23

$\frac{73}{16}$ $73/16$

Explanation:

$p (c) = {(\frac{3}{2})}^{4} - 2 {(\frac{3}{2})}^{2} + 4$ $p(c)=(3/2)^4-2(3/2)^2+4$
$p (c) = (\frac{81}{16}) - 2 (\frac{9}{4}) + 4$ $p(c)=(81/16)-2(9/4)+4$
$p (c) = (\frac{81}{16}) - (\frac{72}{16}) + (\frac{64}{16})$ $p(c)=(81/16)-(72/16)+(64/16)$
$p (c) = \frac{73}{16}$ $p(c)=73/16$

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How do you determine p(c) given $p (x) = x^{4} - 2 x^{2} + 4$ $p(x)=x^4-2x^2+4$ and c=3/2?

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