How do you write the first six terms of the sequence #a_n=(n-1)^2#?

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Answer 1 · 2016-10-10T06:10:44

First six terms are #{0,1,4,9,16,25}#

You can derive the #n^(th)# term by puuting the value of #n# in #a_n=(n-1)^2#

Hence, #a_1=(1-1)^2=0#

#a_2=(2-1)^2=1^2=1#

#a_3=(3-1)^2=2^2=4#

#a_4=(4-1)^2=3^2=9#

#a_5=(5-1)^2=4^2=16#

#a_6=(6-1)^2=5^2=25#

Hence, first six terms are #{0,1,4,9,16,25}#