How do you find the average rate of change of #s(t) = t^3 + t# over the interval [2,4]? Calculus Derivatives Average Rate of Change Over an Interval 1 Answer Mia Oct 10, 2016 #29# Explanation: Average rate: #color(blue)((s(4)-s(2))/(4-2))# #s(4)=4^3+4=64+4=68# #s(2)=2^3+2=8+2=10# #color(blue)((s(4)-s(2))/(4-2))# #=(68-10)/2# #=29# Answer link Related questions How do you find the average rate of change of a function from graph? How do you find the average rate of change of a function between two points? How do you find the average rate of change of #f(x) = sec(x)# from #x=0# to #x=pi/4#? How do you find the average rate of change of #f(x) = tan(x)# from #x=0# to #x=pi/4#? How do you find the rate of change of y with respect to x? How do you find the average rate of change of #y=x^3+1# from #x=1# to #x=3#? What is the relationship between the Average rate of change of a fuction and derivatives? What is the difference between Average rate of change and instantaneous rate of change? What does the Average rate of change of a linear function represent? What is the relationship between the Average rate of change of a function and a secant line? See all questions in Average Rate of Change Over an Interval Impact of this question 2066 views around the world You can reuse this answer Creative Commons License