How do you differentiate f(x)=(3x^3-2x^2+5)^331? Calculus Basic Differentiation Rules Chain Rule 1 Answer Henry W. Oct 11, 2016 (dy)/(dx)=331(9x^2-4x)(3x^3-2x^2+5)^330 Explanation: Using chain rule: (dy)/(dx)=(dy)/(du)*(du)/(dx) In this case, y=(3x^3-2x^2+5)^331 Let u=3x^3-2x^2+5, then (dy)/(du)=331u^330 and (du)/(dx)=9x^2-4x So (dy)/(dx)=331u^330*(9x^2-4x) =331(9x^2-4x)(3x^3-2x^2+5)^330 Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 2048 views around the world You can reuse this answer Creative Commons License