What is the equation of the line that passes through the points #(-1,3)# and #(3, -5)#?

1 Answer
Oct 11, 2016

#y+2x-1=0#

Explanation:

Let's say #A# is the point #(-1,3)# and #B# is the point #(3,-5)#

The equation of a line that passes through two points is #y-y_0=m(x-x_0)#

Replace #x, x_0, y# and #y_0# by the coordinates of the two points to find your slope#=>m#.

It doesn't matter which point you choose to replace #x, x_0, y# and #y_0# with as long as you pair #x# with #y# and #x_0# with #y_0#.

#m=(y-y_0)/(x-x_0)=(-5-3)/(3-(-1))=(-5-3)/(3+1)=-2#

Now, all you have to do is to choose either the coordinates of #A# or #B# to replace in the equation of a line that passes through two points #=>y-y_0=m(x-x_0)#. You are only going to replace #x_0# and #y_0#.

I'm using the point #A# #(-1,3)#

#=>y-y_0=m(x-x_0)#

#=>y-3=-2(x+1)#

#=>y-3=-2x-2#

#=>y+2x-1=0# is your line.

Try to use the other point and you'll see that you'll find the same line.

Hope this helps :)