Question

How do you solve `9^(5k)+8=50`?

Answer 1

`k=0.3402`

Explanation:

As `9^(5k)+8=50`,

`9^(5k)=50-8=42`

or taking logarithm to base `10`, we get

`5klog9=log42`

or `k=log42/(5log9)`

or `k=1.62325/(5xx0.95424)`

or `k=0.3402`