Question

Question #b43a1

Answer 1

see below

Explanation:

`sin(2pi-2x)=-sin2x`

Use `sin(A-B) =sinAcosB-cosAsinB` formula

Left Side:`=sin(2pi-2x)`

`=sin 2pi cos 2x-cos2pisin2x`

`=0*cos2x-1*sin2x`

`=0-sin2x`

`=-sin2x`