How do you multiply #2m^2(2m^2+3m-5)#?

Question

1511 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-11T20:06:54

#4m^4+6m^3-10^2#

Distribute the term outside of the set of parenthesis to each term on the inside of the parenthesis.

So, start with the first term in the parenthesis: #2m^2#

Distribute #2m^2# to #2m^2# and multiply
#2m^2xx2m^2=4m^4#

Next distribute #2m^2# to the second term in the parenthesis: #3m#

#2m^2xx3m=6m^3#

Lastly, distribute #2m^2# to the third and final term in the parenthesis: #-5#

#2m62xx-5=-10m^2#

So, the equation would look like:
#4m^4+6m^3-10^2#

I just expanded it so you could see each individual step