How do you solve #ln3x=5#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Oct 12, 2016 #x=e^5/3=49.471# Explanation: In #ln3x=5#, #ln# refers to Napier logarithm i.e. to base #e# Hence, using definition of logarithm we have #3x=e^5# or #x=e^5/3=148.413/3=49.471# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 3263 views around the world You can reuse this answer Creative Commons License