Question #9cda7
1 Answer
Oct 13, 2016
Explanation:
We will use the following properties of exponents and of logarithms:
#a^(-x) = 1/a^x# #(a^x)^y = a^(xy)# #a^x*a^y = a^(x+y)# #log_a(a^x) = x#
With those