How do you determine dy/dx given #x^2+y^2=sqrt7#?

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Answer 1 · 2016-10-17T11:25:51

We differentiate both sides with respect to x

#d(x^2+y^2)/dx=d(sqrt7)/dx#

#2*x+2y*dy/dx=0#

#x+y*(dy/dx)=0#

#dy/dx=-x/y#

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