Question

How do you solve `2^(x^2-3)=15`?

Answer 1

`x=+-2.628`

Explanation:

`2^(x^2-3)=15`

`hArrx^2-3=log_2 15=log15/log2=1.1761/0.3010=3.9073`

and `x^2=3+3.9073=6.9073`

and `x=sqrt6.9073=+-2.628`