What is the derivative of ln(2x+1)? Calculus Basic Differentiation Rules Chain Rule 1 Answer Henry W. Oct 18, 2016 2/(2x+1) Explanation: y=ln(2x+1) contains a function within a function, i.e. 2x+1 within ln(u). Letting u=2x+1, we can apply chain rule. Chain rule: (dy)/(dx)=(dy)/(du)*(du)/(dx) (dy)/(du)=d/(du)ln(u)=1/u (du)/(dx)=d/(dx)2x+1=2 :.(dy)/(dx)=1/u*2=1/(2x+1)*2=2/(2x+1) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 49724 views around the world You can reuse this answer Creative Commons License