How do you find the value of 1-[30div[7+3(-4)]]1[30÷[7+3(4)]]?

2 Answers
Oct 23, 2016

77

Explanation:

When evaluating expressions with color(blue)"mixed operations"mixed operations we have to follow a certain order.

Follow the procedure as set out in the acronym PEMDAS.

Since there are ' brackets within brackets' start by evaluating the ' inner' brackets and work ' out'.

That is 3(-4)=3xx(-4)=-12larrcolor(red)"innermost bracket"3(4)=3×(4)=12innermost bracket

Now we have.

[7+(-12)]=[7-12]=-5larrcolor(red)" next inner bracket"[7+(12)]=[712]=5 next inner bracket

and finally.

[30÷(-5)]=-6larrcolor(red)"final set of brackets"[30÷(5)]=6final set of brackets

The expression is now.

1-(-6)=1+6=7larrcolor(red)"the value of the expression"1(6)=1+6=7the value of the expression

Oct 23, 2016

77

Explanation:

In any calculation involving different operations, the MOST important thing is to count the number of TERMS first. Each term is kept separate until the last line, and then they are added or subtracted.

Within each term:
- brackets are done first,
-then powers and roots,
-then multiply and divide.

color(blue)(1)color(red)(-[30div[7+3(-4)]]) " "larr1[30÷[7+3(4)]] There are 2 terms

Start with the innermost bracket, then work outwards:

=color(blue)(1)color(red)(-[30div[7color(black)(-12]])1[30÷[712])

=color(blue)(1)color(red)(-[30div[color(black)(-5]])" "larr1[30÷[5]) now divide

=color(blue)(1)color(black)(-[-6])1[6]

=color(blue)(1)color(red)(+6)" "larr1+6 final answer for each term

=77