If I have an equation that reads: #-4y=x-3# and I am solving for #y#, what would the solution be?

Question

I know that I am supposed to divide, but what I don't know is what to do with the negative. Like, would the answer look like: #y=-(x-3)/4# or #y=(-x+3)/4# or are those two the same thing?

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Answer 1 · 2016-10-23T18:56:38

The first one is correct, although it could also be written as #y=(x-3)/-4# or #y=(-(x-3))/4#.

Divide each side by #-4#.

#-4y÷4=y#

#(x-3)÷-4=#

#y=(x-3)/-4 or #
#y=(-(x-3))/4 or #
#y=-(x-3)/4#