Question #c1d5e
1 Answer
Oct 24, 2016
The limit does not exist
Explanation:
The limit
Note that
= x^2|2x-1|
= {(-x^2(2x-1) if x <= 1/2),(x^2(2x-1) if x >= 1/2):}
With that, let's calculate the two one-sided limits at
As we approach
=lim_(x->1/2""^-)-1/x^2
=-1/(1/2)^2
=-4
As we approach
=lim_(x->1/2""^+)1/x^2
=1/(1/2)^2
=4
As