Question #efd42

1 Answer
Oct 26, 2016

Given quadratic equation of m is

#2m^2-16m+8=0#

#=>m^2-8m+4=0#

It being a quasratic equation it will have only two values that satisfy the equation. Let these are a and b.

So #(m-a)(m-b)=0# should be the qudratic equation.

Comparing these two equations
we have

#(m-a)(m-b)=m^2-8m+4#

#m^2-(a+b)m+ab=m^2-8m+4#

Comparing LHS and RHS we get

#a+b=8#

~~~~~~~~~~~~~~~~~~~~~~~~~~±~
For any quadratic equation

#ax^2+bx+c=0#,

if #alpha and beta # are two values of x that satisfy the equation then

#alpha+beta=-b/a and alphabeta=c/a#