What is the slope of the line that passes through (2,5) and (-1,5)?

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Answer 1 · 2016-10-26T19:45:20

$0$ $0$

The formula to find slope is:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

Where $m$ $m$ is the slope

$(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$

Next plug in both set of parenthesis into the equation

$m = \frac{5 - 5}{- 1 - 2}$ $m=(5-5)/(-1-2)$

Solve numerator (top) and denominator (bottom)

$m = \frac{0}{- 3} = 0$ $m=0/-3=0$

Because the slope is $0$ $0$ , the line is horizontal because it has all the same $y$ $y$ coordinate points