How do you solve #-2m ^ { 2} - 6= 0#?

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Answer 1 · 2016-10-27T07:32:02

There are no real solutions.

#-2m^2 -6=0#

Although this is a quadratic # (m^2)# we can use a different method to solve it because there is no #m# term.

Write it as #" "2m^2 = -6" "larr# solve for #m. div 2#

#m^2 = -3" "larr# find the square root

#m = +-sqrt-3#

This is where we hit a problem, because you cannot find the square root of a negative value.

Therefore: there are no Real solutions for this equation