How do you differentiate #r(x)=(e^(41x^2))^3#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Steve M Oct 27, 2016 # r'(x) = 246xe^(123x^2) # Explanation: We have # r = (e^(41x^2))^3 # # :. r = e^(123x^2) # # :. (dr)/dx = (123)e^(123x^2)(2x) # # :. (dr)/dx = 246xe^(123x^2) # Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1121 views around the world You can reuse this answer Creative Commons License