Question

How do you solve `log_8 48-log_8 w=log_8 6`?

Answer 1

Answer is `w` = 8.

Explanation:

`log_8 48-log_8w=log_8 6`
`:.` `log48/log8-logw/log8=log6/log8`
`:.` `log48-logw=log6`
`:.` `log8*6-logw=log6`
`:.` `log8+log6-logw=log6`
`:. log8-logw=0`
`:.logw=log8`
`:.w=8`. (answer).