Question

The gas inside of a container exerts `18 Pa` of pressure and is at a temperature of `350K`. If the temperature of the gas changes to `240K` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`12.3428pa`

Explanation:

in this case,
Gay Lussac's law will be applied as the volume stays constant.
from the law, we know that,
`P_1/T_1=P_2/T_2`
here,
`P_1=18pa`
`T_1=350k`
`T_2=240k`
now, we have to find `P_2`
putting the values in the equation, we get,

`18/350=P_2/240`
`or, P_2=(240*18)/350`
`or, P_2=12.3428pa`