How do you factor 4n^2-20n+24?
1 Answer
Oct 30, 2016
Explanation:
The first step is to take out the
color(blue)"common factor" of 4, from each term.
rArr4n^2-20n+24=4(n^2-5n+6) To factorise the quadratic expression in the bracket.
Consider the factors of 6 which also sum to -5.
These are - 3 and - 2.
since
-3xx-2=+6" and " -3+(-2)=-5
rArrn^2-5n+6=(n-2)(n-3)
rArr4n^2-20n+24=4(n-2)(n-3)