How do you factor 4n^2-20n+24?

1 Answer
Oct 30, 2016

4(n-2)(n-3)

Explanation:

The first step is to take out the color(blue)"common factor" of 4, from each term.

rArr4n^2-20n+24=4(n^2-5n+6)

To factorise the quadratic expression in the bracket.

Consider the factors of 6 which also sum to -5.

These are - 3 and - 2.

since -3xx-2=+6" and " -3+(-2)=-5

rArrn^2-5n+6=(n-2)(n-3)

rArr4n^2-20n+24=4(n-2)(n-3)