What is the set of numbers to which #-sqrt22# belong?

1 Answer

The #-sqrt22# is equal to #-sqrt22=-sqrt(2*11)=-(sqrt2*sqrt11)#

Hence #sqrt2# , #sqrt11# are irrationals , #-sqrt22# is irrational.

When a number like #sqrta# can simplify to the form #p/q# where #p,q# where are natural number then it is called rational.

For example #-sqrt9=-sqrt(3^2)=-3#

Of course irrational numbers belong to the set of real numbers like the rationals , integers and natural numbers.