How do you simplify #\sqrt{98x^{4} y^{6} z^{2}}#?

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Answer 1 · 2016-10-02T01:08:38

#7 sqrt(2) x^(2) y^(3) z#

We have: #sqrt(98 x^(4) y^(6) z^(2))#

Let's express #98# as a product:

#= sqrt((14 cdot 7) x^(4) y^(6) z^(2))#

#= sqrt((2 cdot 7 cdot 7) x^(4) y^(6) z^(2))#

#= sqrt(2 cdot 7^(2) x^(4) y^(6) z^(2))#

#= sqrt(2) cdot 7 cdot x^(2) cdot y^(3) cdot z#

#= 7 sqrt(2) x^(2) y^(3) z#

Answer 2 · 2016-10-31T13:47:49

Answer is #sqrt(98x^4y^6z^2##=##7sqrt(2)x^2y^3z#.

#sqrt(98x^4y^6z^2# #=sqrt(49*2*(x^2)^2*y^2*(y^2)^2*z^2# #=7sqrt(2)x^2y^3z#. (answer).