Question

How do you differentiate `f(x)=cos(-3x^2+2)^2`?

Answer 1

`f'(x)=12x(-3x^2+2) sin(-3x^2+2)^2`

Explanation:

`f(x)=cos(-3x^2+2)^2`

`f'(x)=-sin(-3x^2+2)^2 * 2(-3x^2+2) *-6x`

`f'(x)=12x(-3x^2+2) sin(-3x^2+2)^2`