How do you evaluate the limit #(x^2-25)/(x^2-4x-5)# as x approaches 5?

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Answer 1 · 2016-11-01T13:15:27

We start by factoring both the numerator and the denominator.

#=lim_(x->5)((x + 5)(x- 5))/((x - 5)(x + 1))#

#=lim_(x -> 5) (x + 5)/(x + 1)#

#=(5 + 5)/(5 + 1)#

#=10/6#

#=5/3#

Hopefully this helps!