Question

How do you differentiate `f(x)= sin(pix-2)^3` using the chain rule.?

Answer 1

`f'(x)=cos(pix-2)^3 * 3(pix-2)^2 * pi`

Explanation:

`f(x)=sin(pix-2)^3`

`f'(x)=cos(pix-2)^3 * 3(pix-2)^2 * pi`