Question

How do you differentiate `e^((2-x)^2)` using the chain rule?

Answer 1

`y'=-2(2-x)e^((2-x)^2)`

Explanation:

`y=e^((2-x)^2)`

Use the rule
`e^u =e^u *u'`

`y'=e^((2-x)^2) 2(2-x)*-1`

`y'=-2(2-x)e^((2-x)^2)`