Question

How do you use the chain rule to differentiate `y=4(x^2-7x+3)^(-3/4)`?

Answer 1

`y'=(-3(2x-7))/(x^2-7x+3)^(7/4) = (-6x+21)/(x^2-7x+3)^(7/4)`

Explanation:

`y=4(x^2-7x+3)^(-3/4)`

`y'=-3(x^2-7x+3)^(-7/4)*(2x-7)`

`y'=(-3(2x-7))/(x^2-7x+3)^(7/4) = (-6x+21)/(x^2-7x+3)^(7/4)`