Question

How do you differentiate `tan5y-ysinx+3xy^2=9`?

Answer 1

`dy/dx=(ycosx-3y^2)/(5sec^2 (5y) -sinx +6xy )`

Explanation:

`tan 5y-ysinx+3xy^2=9`

`5sec^2 (5y) dy/dx-ycosx-sinx dy/dx+3y^2+6xy dy/dx=0`

`5sec^2 (5y) dy/dx-sinx dy/dx+6xy dy/dx=ycosx-3y^2`

`dy/dx(5sec^2 (5y) -sinx +6xy )=ycosx-3y^2`

`dy/dx=(ycosx-3y^2)/(5sec^2 (5y) -sinx +6xy )`