How to find instantaneous rate of change for #f(x) = 3x^2+4x# at (1, 7)?

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Answer 1 · 2016-11-04T17:07:41

Instantaneous rate of change is #f' (1) = 10#.

Instantaneus rate of change is the derivative calculated in a given point.

For the function:

#f (x) = 3 x^2 + 4 x#

derivative is:

#f ' (x) = 6 x + 4#

Then, in point #(1, 7)#, we have:

#f ' (1) = 6 cdot 1 + 4 = 10#.