Question

How do you find `(d^2y)/(dx^2)` given `y=x^(9/4)`?

Answer 1

The answer is `45/16*x^(1/4)`

Explanation:

We use `(x^n)'=nx^(n-1)`
`y=x^(9/4)`
`dy/dx=9/4*x^(9/4-1)=9/4x^(5/4)`
`(d^2x)/dy^2=9/4*5/4x^(5/4-1)=45/16*x^(1/4)`