Question

How do you find vertical, horizontal and oblique asymptotes for `y=3/(x-2)+1`?

Answer 1

The vertical asymptote is `x=2`
The horizontal asymptote is `y=1`
There is no oblique asymptote.

Explanation:

As we cannot divide by `0`, the vertical asymptote is `x=2`
And `lim_(x->+-oo)y=1`
So `y=1`is a horizontal asymptote.
There is no oblique asymptote as the degree of the numerator `=` the degree of the denominator
graph{(y-1-3/(x-2))(y-1)=0 [-14.24, 14.24, -7.12, 7.12]}