The gas inside of a container exerts #24 Pa# of pressure and is at a temperature of #220 ^o K#. If the pressure in the container changes to #52 Pa# with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2016-11-10T06:34:05

THe new temperature is #=477 K#

Use the equation #P_1/T_1=P_2/T_2#

Pressure #P_1=24 Pa#

Temperature #T_1=220 K#

Pressure #P_2=52 Pa#

Temperature #T_2=P_2/P_1T_1=52/24*220=477K#