Question

If `12 L` of a gas at room temperature exerts a pressure of `9 kPa` on its container, what pressure will the gas exert if the container's volume changes to `3 L`?

Answer 1

The pressure is `=36kPa`

Explanation:

Use `P_1V_1=P_2V_2` (Boyle's law)
`P_1=9kPa`
`V_1=12l`
`V_2=3l`

`P_2=(P_1V_1)/V_2=(9*12)/3=36 kPa`