Question

Could any one tell me how to solve this equation? Thanks :)

Answer 1

`x = 42/55`

Explanation:

`3 x/2+ 7 2/3x+2=24/2-x" "larr` change to improper fractions

`(6+x)/2 + (23x)/3 +2 = 12-x" "larr xx 6`

`(cancel6^3xx(6+x))/cancel2 + (cancel6^2xx(23x))/cancel3 +6xx2 = 6xx12-x xx6`

`18+3x + 46x +12 =72 -6x`

`49x+6x = 72-18-12`

`55x = 42`

`x = 42/55`