Question

How do you evaluate `log_(1/9) (1/81)`?

Answer 1

`log_(1/9)(1/81)=2`

Explanation:

As `(1/9)^2=1/81`,

by the definition of logarithm that `if a^b=m`, then `log_a m=b`, we get

`log_(1/9)(1/81)=2`